WSJT-X/libm65/grid2deg.f90

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Fortran
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subroutine grid2deg(grid0,dlong,dlat)
! Converts Maidenhead grid locator to degrees of West longitude
! and North latitude.
character*6 grid0,grid
character*1 g1,g2,g3,g4,g5,g6
grid=grid0
i=ichar(grid(5:5))
if(grid(5:5).eq.' ' .or. i.le.64 .or. i.ge.128) grid(5:6)='mm'
if(grid(1:1).ge.'a' .and. grid(1:1).le.'z') grid(1:1)= &
char(ichar(grid(1:1))+ichar('A')-ichar('a'))
if(grid(2:2).ge.'a' .and. grid(2:2).le.'z') grid(2:2)= &
char(ichar(grid(2:2))+ichar('A')-ichar('a'))
if(grid(5:5).ge.'A' .and. grid(5:5).le.'Z') grid(5:5)= &
char(ichar(grid(5:5))-ichar('A')+ichar('a'))
if(grid(6:6).ge.'A' .and. grid(6:6).le.'Z') grid(6:6)= &
char(ichar(grid(6:6))-ichar('A')+ichar('a'))
g1=grid(1:1)
g2=grid(2:2)
g3=grid(3:3)
g4=grid(4:4)
g5=grid(5:5)
g6=grid(6:6)
nlong = 180 - 20*(ichar(g1)-ichar('A'))
n20d = 2*(ichar(g3)-ichar('0'))
xminlong = 5*(ichar(g5)-ichar('a')+0.5)
dlong = nlong - n20d - xminlong/60.0
nlat = -90+10*(ichar(g2)-ichar('A')) + ichar(g4)-ichar('0')
xminlat = 2.5*(ichar(g6)-ichar('a')+0.5)
dlat = nlat + xminlat/60.0
return
end subroutine grid2deg