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97 lines
2.3 KiB
Fortran
97 lines
2.3 KiB
Fortran
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subroutine getpfx1(callsign,k,nv2)
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character*12 callsign0,callsign,lof,rof
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character*8 c
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character addpfx*8,tpfx*4,tsfx*3
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logical ispfx,issfx,invalid
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common/pfxcom/addpfx
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include 'pfx.f90'
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callsign0=callsign
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nv2=0
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iz=index(callsign,' ') - 1
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if(iz.lt.0) iz=12
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islash=index(callsign(1:iz),'/')
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k=0
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c=' '
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if(islash.gt.0 .and. islash.le.(iz-4)) then
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! Add-on prefix
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c=callsign(1:islash-1)
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callsign=callsign(islash+1:iz)
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do i=1,NZ
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if(pfx(i)(1:4).eq.c) then
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k=i
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go to 10
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endif
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enddo
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if(addpfx.eq.c) then
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k=449
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go to 10
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endif
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else if(islash.eq.(iz-1)) then
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! Add-on suffix
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c=callsign(islash+1:iz)
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callsign=callsign(1:islash-1)
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do i=1,NZ2
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if(sfx(i).eq.c(1:1)) then
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k=400+i
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go to 10
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endif
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enddo
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endif
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10 if(islash.ne.0 .and.k.eq.0) then
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! Original JT65 would force this compound callsign to be treated as
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! plain text. In JT65v2, we will encode the prefix or suffix into nc1.
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! The task here is to compute the proper value of k.
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lof=callsign0(:islash-1)
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rof=callsign0(islash+1:)
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llof=len_trim(lof)
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lrof=len_trim(rof)
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ispfx=(llof.gt.0 .and. llof.le.4)
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issfx=(lrof.gt.0 .and. lrof.le.3)
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invalid=.not.(ispfx.or.issfx)
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if(ispfx.and.issfx) then
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if(llof.lt.3) issfx=.false.
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if(lrof.lt.3) ispfx=.false.
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if(ispfx.and.issfx) then
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i=ichar(callsign0(islash-1:islash-1))
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if(i.ge.ichar('0') .and. i.le.ichar('9')) then
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issfx=.false.
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else
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ispfx=.false.
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endif
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endif
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endif
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if(invalid) then
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k=-1
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else
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if(ispfx) then
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tpfx=lof
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k=nchar(tpfx(1:1))
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k=37*k + nchar(tpfx(2:2))
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k=37*k + nchar(tpfx(3:3))
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k=37*k + nchar(tpfx(4:4))
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nv2=1
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i=index(callsign0,'/')
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callsign=callsign0(:i-1)
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callsign=callsign0(i+1:)
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endif
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if(issfx) then
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tsfx=rof
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k=nchar(tsfx(1:1))
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k=37*k + nchar(tsfx(2:2))
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k=37*k + nchar(tsfx(3:3))
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nv2=2
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i=index(callsign0,'/')
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callsign=callsign0(:i-1)
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endif
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endif
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endif
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return
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end subroutine getpfx1
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