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80 lines
2.0 KiB
Fortran
80 lines
2.0 KiB
Fortran
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subroutine packcall(callsign,ncall,text)
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! Pack a valid callsign into a 28-bit integer.
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parameter (NBASE=37*36*10*27*27*27)
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character callsign*6,c*1,tmp*6
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logical text
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text=.false.
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! Work-around for Swaziland prefix:
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if(callsign(1:4).eq.'3DA0') callsign='3D0'//callsign(5:6)
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if(callsign(1:3).eq.'CQ ') then
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ncall=NBASE + 1
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if(callsign(4:4).ge.'0' .and. callsign(4:4).le.'9' .and. &
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callsign(5:5).ge.'0' .and. callsign(5:5).le.'9' .and. &
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callsign(6:6).ge.'0' .and. callsign(6:6).le.'9') then
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read(callsign(4:6),*) nfreq
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ncall=NBASE + 3 + nfreq
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endif
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return
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else if(callsign(1:4).eq.'QRZ ') then
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ncall=NBASE + 2
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return
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else if(callsign(1:3).eq.'DE ') then
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ncall=267796945
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return
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endif
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tmp=' '
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if(callsign(3:3).ge.'0' .and. callsign(3:3).le.'9') then
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tmp=callsign
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else if(callsign(2:2).ge.'0' .and. callsign(2:2).le.'9') then
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if(callsign(6:6).ne.' ') then
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text=.true.
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return
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endif
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tmp=' '//callsign(:5)
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else
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text=.true.
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return
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endif
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do i=1,6
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c=tmp(i:i)
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if(c.ge.'a' .and. c.le.'z') &
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tmp(i:i)=char(ichar(c)-ichar('a')+ichar('A'))
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enddo
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n1=0
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if((tmp(1:1).ge.'A'.and.tmp(1:1).le.'Z').or.tmp(1:1).eq.' ') n1=1
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if(tmp(1:1).ge.'0' .and. tmp(1:1).le.'9') n1=1
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n2=0
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if(tmp(2:2).ge.'A' .and. tmp(2:2).le.'Z') n2=1
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if(tmp(2:2).ge.'0' .and. tmp(2:2).le.'9') n2=1
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n3=0
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if(tmp(3:3).ge.'0' .and. tmp(3:3).le.'9') n3=1
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n4=0
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if((tmp(4:4).ge.'A'.and.tmp(4:4).le.'Z').or.tmp(4:4).eq.' ') n4=1
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n5=0
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if((tmp(5:5).ge.'A'.and.tmp(5:5).le.'Z').or.tmp(5:5).eq.' ') n5=1
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n6=0
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if((tmp(6:6).ge.'A'.and.tmp(6:6).le.'Z').or.tmp(6:6).eq.' ') n6=1
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if(n1+n2+n3+n4+n5+n6 .ne. 6) then
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text=.true.
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return
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endif
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ncall=nchar(tmp(1:1))
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ncall=36*ncall+nchar(tmp(2:2))
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ncall=10*ncall+nchar(tmp(3:3))
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ncall=27*ncall+nchar(tmp(4:4))-10
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ncall=27*ncall+nchar(tmp(5:5))-10
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ncall=27*ncall+nchar(tmp(6:6))-10
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return
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end subroutine packcall
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