WSJT-X/libm65/packmsg.f

105 lines
3.3 KiB
FortranFixed
Raw Normal View History

subroutine packmsg(msg,dat)
parameter (NBASE=37*36*10*27*27*27)
parameter (NBASE2=262178562)
character*22 msg
integer dat(12)
character*12 c1,c2,c2z
character*4 c3
character*6 grid6
c character*3 dxcc !Where is DXCC implemented?
logical text1,text2,text3
C Convert all letters to upper case
do i=1,22
if(msg(i:i).ge.'a' .and. msg(i:i).le.'z')
+ msg(i:i)= char(ichar(msg(i:i))+ichar('A')-ichar('a'))
enddo
C See if it's a CQ message
if(msg(1:3).eq.'CQ ') then
i=3
C ... and if so, does it have a reply frequency?
if(msg(4:4).ge.'0' .and. msg(4:4).le.'9' .and.
+ msg(5:5).ge.'0' .and. msg(5:5).le.'9' .and.
+ msg(6:6).ge.'0' .and. msg(6:6).le.'9') i=7
go to 1
endif
do i=1,22
if(msg(i:i).eq.' ') go to 1 !Get 1st blank
enddo
go to 10 !Consider msg as plain text
1 ia=i
c1=msg(1:ia-1)
do i=ia+1,22
if(msg(i:i).eq.' ') go to 2 !Get 2nd blank
enddo
go to 10 !Consider msg as plain text
2 ib=i
c2=msg(ia+1:ib-1)
do i=ib+1,22
if(msg(i:i).eq.' ') go to 3 !Get 3rd blank
enddo
go to 10 !Consider msg as plain text
3 ic=i
c3=' '
if(ic.ge.ib+1) c3=msg(ib+1:ic)
if(c3.eq.'OOO ') c3=' ' !Strip out the OOO flag
call getpfx1(c1,k1,nv2)
if(nv2.ne.0) go to 10
call packcall(c1,nc1,text1)
c2z=c2
call getpfx1(c2,k2,nv2)
call packcall(c2,nc2,text2)
if(nv2.eq.0) then
if(k1.lt.0 .or. k2.lt.0 .or. k1*k2.ne.0) go to 10
if(k2.gt.0) k2=k2+450
k=max(k1,k2)
if(k.gt.0) then
call k2grid(k,grid6)
c3=grid6(:4)
endif
endif
call packgrid(c3,ng,text3)
if(nv2.eq.0 .and. (.not.text1) .and. (.not.text2) .and.
+ (.not.text3)) go to 20
if(nv2.gt.0) then
if(nv2.eq.1) then
if(c1(1:3).eq.'CQ ') nc1=262178563 + k2
if(c1(1:4).eq.'QRZ ') nc1=264002072 + k2
if(c1(1:3).eq.'DE ') nc1=265825581 + k2
endif
if(nv2.eq.2) then
if(c1(1:3).eq.'CQ ') nc1=267649090 + k2
if(c1(1:4).eq.'QRZ ') nc1=267698375 + k2
if(c1(1:3).eq.'DE ') nc1=267747660 + k2
endif
go to 20
endif
C The message will be treated as plain text.
10 call packtext(msg,nc1,nc2,ng)
ng=ng+32768
C Encode data into 6-bit words
20 dat(1)=iand(ishft(nc1,-22),63) !6 bits
dat(2)=iand(ishft(nc1,-16),63) !6 bits
dat(3)=iand(ishft(nc1,-10),63) !6 bits
dat(4)=iand(ishft(nc1, -4),63) !6 bits
dat(5)=4*iand(nc1,15)+iand(ishft(nc2,-26),3) !4+2 bits
dat(6)=iand(ishft(nc2,-20),63) !6 bits
dat(7)=iand(ishft(nc2,-14),63) !6 bits
dat(8)=iand(ishft(nc2, -8),63) !6 bits
dat(9)=iand(ishft(nc2, -2),63) !6 bits
dat(10)=16*iand(nc2,3)+iand(ishft(ng,-12),15) !2+4 bits
dat(11)=iand(ishft(ng,-6),63)
dat(12)=iand(ng,63)
return
end