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170 lines
6.3 KiB
C++
170 lines
6.3 KiB
C++
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// find_root_example.cpp
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// Copyright Paul A. Bristow 2007, 2010.
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// Use, modification and distribution are subject to the
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// Boost Software License, Version 1.0.
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// (See accompanying file LICENSE_1_0.txt
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// or copy at http://www.boost.org/LICENSE_1_0.txt)
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// Example of using root finding.
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// Note that this file contains Quickbook mark-up as well as code
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// and comments, don't change any of the special comment mark-ups!
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//[root_find1
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/*`
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First we need some includes to access the normal distribution
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(and some std output of course).
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*/
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#include <boost/math/tools/roots.hpp> // root finding.
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#include <boost/math/distributions/normal.hpp> // for normal_distribution
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using boost::math::normal; // typedef provides default type is double.
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#include <iostream>
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using std::cout; using std::endl; using std::left; using std::showpoint; using std::noshowpoint;
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#include <iomanip>
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using std::setw; using std::setprecision;
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#include <limits>
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using std::numeric_limits;
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#include <stdexcept>
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//] //[/root_find1]
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int main()
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{
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cout << "Example: Normal distribution, root finding.";
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try
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{
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//[root_find2
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/*`A machine is set to pack 3 kg of ground beef per pack.
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Over a long period of time it is found that the average packed was 3 kg
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with a standard deviation of 0.1 kg.
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Assuming the packing is normally distributed,
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we can find the fraction (or %) of packages that weigh more than 3.1 kg.
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*/
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double mean = 3.; // kg
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double standard_deviation = 0.1; // kg
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normal packs(mean, standard_deviation);
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double max_weight = 3.1; // kg
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cout << "Percentage of packs > " << max_weight << " is "
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<< cdf(complement(packs, max_weight)) << endl; // P(X > 3.1)
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double under_weight = 2.9;
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cout <<"fraction of packs <= " << under_weight << " with a mean of " << mean
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<< " is " << cdf(complement(packs, under_weight)) << endl;
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// fraction of packs <= 2.9 with a mean of 3 is 0.841345
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// This is 0.84 - more than the target 0.95
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// Want 95% to be over this weight, so what should we set the mean weight to be?
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// KK StatCalc says:
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double over_mean = 3.0664;
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normal xpacks(over_mean, standard_deviation);
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cout << "fraction of packs >= " << under_weight
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<< " with a mean of " << xpacks.mean()
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<< " is " << cdf(complement(xpacks, under_weight)) << endl;
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// fraction of packs >= 2.9 with a mean of 3.06449 is 0.950005
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double under_fraction = 0.05; // so 95% are above the minimum weight mean - sd = 2.9
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double low_limit = standard_deviation;
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double offset = mean - low_limit - quantile(packs, under_fraction);
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double nominal_mean = mean + offset;
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normal nominal_packs(nominal_mean, standard_deviation);
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cout << "Setting the packer to " << nominal_mean << " will mean that "
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<< "fraction of packs >= " << under_weight
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<< " is " << cdf(complement(nominal_packs, under_weight)) << endl;
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/*`
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Setting the packer to 3.06449 will mean that fraction of packs >= 2.9 is 0.95.
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Setting the packer to 3.13263 will mean that fraction of packs >= 2.9 is 0.99,
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but will more than double the mean loss from 0.0644 to 0.133.
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Alternatively, we could invest in a better (more precise) packer with a lower standard deviation.
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To estimate how much better (how much smaller standard deviation) it would have to be,
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we need to get the 5% quantile to be located at the under_weight limit, 2.9
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*/
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double p = 0.05; // wanted p th quantile.
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cout << "Quantile of " << p << " = " << quantile(packs, p)
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<< ", mean = " << packs.mean() << ", sd = " << packs.standard_deviation() << endl; //
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/*`
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Quantile of 0.05 = 2.83551, mean = 3, sd = 0.1
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With the current packer (mean = 3, sd = 0.1), the 5% quantile is at 2.8551 kg,
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a little below our target of 2.9 kg.
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So we know that the standard deviation is going to have to be smaller.
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Let's start by guessing that it (now 0.1) needs to be halved, to a standard deviation of 0.05
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*/
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normal pack05(mean, 0.05);
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cout << "Quantile of " << p << " = " << quantile(pack05, p)
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<< ", mean = " << pack05.mean() << ", sd = " << pack05.standard_deviation() << endl;
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cout <<"Fraction of packs >= " << under_weight << " with a mean of " << mean
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<< " and standard deviation of " << pack05.standard_deviation()
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<< " is " << cdf(complement(pack05, under_weight)) << endl;
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//
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/*`
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Fraction of packs >= 2.9 with a mean of 3 and standard deviation of 0.05 is 0.9772
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So 0.05 was quite a good guess, but we are a little over the 2.9 target,
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so the standard deviation could be a tiny bit more. So we could do some
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more guessing to get closer, say by increasing to 0.06
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*/
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normal pack06(mean, 0.06);
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cout << "Quantile of " << p << " = " << quantile(pack06, p)
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<< ", mean = " << pack06.mean() << ", sd = " << pack06.standard_deviation() << endl;
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cout <<"Fraction of packs >= " << under_weight << " with a mean of " << mean
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<< " and standard deviation of " << pack06.standard_deviation()
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<< " is " << cdf(complement(pack06, under_weight)) << endl;
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/*`
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Fraction of packs >= 2.9 with a mean of 3 and standard deviation of 0.06 is 0.9522
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Now we are getting really close, but to do the job properly,
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we could use root finding method, for example the tools provided, and used elsewhere,
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in the Math Toolkit, see __root_finding_without_derivatives.
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But in this normal distribution case, we could be even smarter and make a direct calculation.
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*/
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//] [/root_find2]
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}
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catch(const std::exception& e)
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{ // Always useful to include try & catch blocks because default policies
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// are to throw exceptions on arguments that cause errors like underflow, overflow.
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// Lacking try & catch blocks, the program will abort without a message below,
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// which may give some helpful clues as to the cause of the exception.
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std::cout <<
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"\n""Message from thrown exception was:\n " << e.what() << std::endl;
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}
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return 0;
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} // int main()
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/*
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Output is:
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//[root_find_output
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Autorun "i:\boost-06-05-03-1300\libs\math\test\Math_test\debug\find_root_example.exe"
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Example: Normal distribution, root finding.Percentage of packs > 3.1 is 0.158655
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fraction of packs <= 2.9 with a mean of 3 is 0.841345
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fraction of packs >= 2.9 with a mean of 3.0664 is 0.951944
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Setting the packer to 3.06449 will mean that fraction of packs >= 2.9 is 0.95
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Quantile of 0.05 = 2.83551, mean = 3, sd = 0.1
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Quantile of 0.05 = 2.91776, mean = 3, sd = 0.05
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Fraction of packs >= 2.9 with a mean of 3 and standard deviation of 0.05 is 0.97725
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Quantile of 0.05 = 2.90131, mean = 3, sd = 0.06
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Fraction of packs >= 2.9 with a mean of 3 and standard deviation of 0.06 is 0.95221
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//] [/root_find_output]
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*/
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