WSJT-X/lib/getpfx1.f90

98 lines
2.4 KiB
Fortran
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subroutine getpfx1(callsign,k,nv2)
character*12 callsign0,callsign,lof,rof
character*8 c
character addpfx*8,tpfx*4,tsfx*3
logical ispfx,issfx,invalid
common/pfxcom/addpfx
include 'pfx.f90'
callsign0=callsign
nv2=0
iz=index(callsign,' ') - 1
if(iz.lt.0) iz=12
islash=index(callsign(1:iz),'/')
k=0
if(k.eq.0) go to 10 !### Always use JT65v2 ###
c=' '
if(islash.gt.0 .and. islash.le.(iz-4)) then
! Add-on prefix
c=callsign(1:islash-1)
callsign=callsign(islash+1:iz)
do i=1,NZ
if(pfx(i)(1:4).eq.c) then
k=i
go to 10
endif
enddo
if(addpfx.eq.c) then
k=449
go to 10
endif
else if(islash.eq.(iz-1)) then
! Add-on suffix
c=callsign(islash+1:iz)
callsign=callsign(1:islash-1)
do i=1,NZ2
if(sfx(i).eq.c(1:1)) then
k=400+i
go to 10
endif
enddo
endif
10 if(islash.ne.0 .and.k.eq.0) then
! Original JT65 would force this compound callsign to be treated as
! plain text. In JT65v2, we will encode the prefix or suffix into nc1.
! The task here is to compute the proper value of k.
lof=callsign0(:islash-1)
rof=callsign0(islash+1:)
llof=len_trim(lof)
lrof=len_trim(rof)
ispfx=(llof.gt.0 .and. llof.le.4)
issfx=(lrof.gt.0 .and. lrof.le.3)
invalid=.not.(ispfx.or.issfx)
if(ispfx.and.issfx) then
if(llof.lt.3) issfx=.false.
if(lrof.lt.3) ispfx=.false.
if(ispfx.and.issfx) then
i=ichar(callsign0(islash-1:islash-1))
if(i.ge.ichar('0') .and. i.le.ichar('9')) then
issfx=.false.
else
ispfx=.false.
endif
endif
endif
if(invalid) then
k=-1
else
if(ispfx) then
tpfx=lof(1:4)
k=nchar(tpfx(1:1))
k=37*k + nchar(tpfx(2:2))
k=37*k + nchar(tpfx(3:3))
k=37*k + nchar(tpfx(4:4))
nv2=1
i=index(callsign0,'/')
callsign=callsign0(:i-1)
callsign=callsign0(i+1:)
endif
if(issfx) then
tsfx=rof(1:3)
k=nchar(tsfx(1:1))
k=37*k + nchar(tsfx(2:2))
k=37*k + nchar(tsfx(3:3))
nv2=2
i=index(callsign0,'/')
callsign=callsign0(:i-1)
endif
endif
endif
return
end subroutine getpfx1