subroutine afc65b(cx,npts,fsample,nflip,mode65,a,ccfbest,dtbest) ! Find delta f, f1, f2 ==> a(1:3) complex cx(npts) real a(5),deltaa(5) a=0. a1=0. a2=0. i2=8*mode65 i1=-i2 j2=8*mode65 j1=-j2 ccfmax=0. istep=2*mode65 do iter=1,2 do i=i1,i2,istep a(1)=i do j=j1,j2,istep a(2)=j chisq=fchisq65(cx,npts,fsample,nflip,a,ccf,dtmax) if(ccf.gt.ccfmax) then a1=a(1) a2=a(2) ccfmax=ccf endif ! write(81,3081) istep,i1,i2,j1,j2,i,j,ccf,ccfmax,dtmax,a1,a2 !3081 format(7i4,5f8.2) enddo enddo i1=int(a1)-istep i2=int(a1)+istep j1=int(a2)-istep j2=int(a2)+istep istep=1 enddo ! a(1)=0. ! a(2)=0. a(1)=a1 a(2)=a2 a(3)=0. a(4)=0. deltaa(1)=2.0*mode65 deltaa(2)=2.0*mode65 deltaa(3)=1.0 nterms=2 !Maybe 2 is enough? ! Start the iteration chisqr=0. chisqr0=1.e6 do iter=1,100 !How many iters is enough? do j=1,nterms chisq1=fchisq65(cx,npts,fsample,nflip,a,ccfmax,dtmax) fn=0. delta=deltaa(j) 10 a(j)=a(j)+delta chisq2=fchisq65(cx,npts,fsample,nflip,a,ccfmax,dtmax) if(chisq2.eq.chisq1) go to 10 if(chisq2.gt.chisq1) then delta=-delta !Reverse direction a(j)=a(j)+delta tmp=chisq1 chisq1=chisq2 chisq2=tmp endif 20 fn=fn+1.0 a(j)=a(j)+delta chisq3=fchisq65(cx,npts,fsample,nflip,a,ccfmax,dtmax) if(chisq3.lt.chisq2) then chisq1=chisq2 chisq2=chisq3 go to 20 endif ! Find minimum of parabola defined by last three points delta=delta*(1./(1.+(chisq1-chisq2)/(chisq3-chisq2))+0.5) a(j)=a(j)-delta deltaa(j)=deltaa(j)*fn/3. ! write(*,4000) iter,j,a(1:2),-chisq2 !4000 format(2i2,4f9.4) enddo chisqr=fchisq65(cx,npts,fsample,nflip,a,ccfmax,dtmax) fdiff=chisqr/chisqr0-1.0 ! write(*,4000) 0,0,a(1:2),-chisqr,fdiff if(abs(fdiff).lt.0.0001) exit chisqr0=chisqr enddo ccfbest=ccfmax * (1378.125/fsample)**2 dtbest=dtmax return end subroutine afc65b