subroutine packmsg(msg,dat,text) parameter (NBASE=37*36*10*27*27*27) parameter (NBASE2=262178562) character*22 msg integer dat(12) character*12 c1,c2 character*4 c3 character*6 grid6 logical text1,text2,text3,text text=.false. C Convert all letters to upper case iz=22 do i=1,22 if(msg(i:i).ge.'a' .and. msg(i:i).le.'z') + msg(i:i)= char(ichar(msg(i:i))+ichar('A')-ichar('a')) if(msg(i:i).ne.' ') iz=i enddo do iter=1,5 !Collapse multiple blanks into one ib2=index(msg(1:iz),' ') if(ib2.lt.1) go to 5 msg=msg(1:ib2)//msg(ib2+2:) iz=iz-1 enddo C See if it's a CQ message 5 if(msg(1:3).eq.'CQ ') then i=3 C ... and if so, does it have a reply frequency? if(msg(4:4).ge.'0' .and. msg(4:4).le.'9' .and. + msg(5:5).ge.'0' .and. msg(5:5).le.'9' .and. + msg(6:6).ge.'0' .and. msg(6:6).le.'9') i=7 go to 1 endif do i=1,22 if(msg(i:i).eq.' ') go to 1 !Get 1st blank enddo go to 10 !Consider msg as plain text 1 ia=i c1=msg(1:ia-1) do i=ia+1,22 if(msg(i:i).eq.' ') go to 2 !Get 2nd blank enddo go to 10 !Consider msg as plain text 2 ib=i c2=msg(ia+1:ib-1) do i=ib+1,22 if(msg(i:i).eq.' ') go to 3 !Get 3rd blank enddo go to 10 !Consider msg as plain text 3 ic=i c3=' ' if(ic.ge.ib+1) c3=msg(ib+1:ic) if(c3.eq.'OOO ') c3=' ' !Strip out the OOO flag call getpfx1(c1,k1,junk) call packcall(c1,nc1,text1) call getpfx1(c2,k2,nv2) call packcall(c2,nc2,text2) if(nv2.eq.0) then if(k1.lt.0 .or. k2.lt.0 .or. k1*k2.ne.0) go to 10 if(k2.gt.0) k2=k2+450 k=max(k1,k2) if(k.gt.0) then call k2grid(k,grid6) c3=grid6(:4) endif endif call packgrid(c3,ng,text3) if(nv2.eq.0 .and. (.not.text1) .and. (.not.text2) .and. + (.not.text3)) go to 20 if(nv2.gt.0) then if(nv2.eq.1) then if(c1(1:3).eq.'CQ ') nc1=262178563 + k2 if(c1(1:4).eq.'QRZ ') nc1=264002072 + k2 if(c1(1:3).eq.'DE ') nc1=265825581 + k2 endif if(nv2.eq.2) then if(c1(1:3).eq.'CQ ') nc1=267649090 + k2 if(c1(1:4).eq.'QRZ ') nc1=267698375 + k2 if(c1(1:3).eq.'DE ') nc1=267747660 + k2 endif go to 20 endif C The message will be treated as plain text. 10 text=.true. call packtext(msg,nc1,nc2,ng) ng=ng+32768 C Encode data into 6-bit words 20 dat(1)=iand(ishft(nc1,-22),63) !6 bits dat(2)=iand(ishft(nc1,-16),63) !6 bits dat(3)=iand(ishft(nc1,-10),63) !6 bits dat(4)=iand(ishft(nc1, -4),63) !6 bits dat(5)=4*iand(nc1,15)+iand(ishft(nc2,-26),3) !4+2 bits dat(6)=iand(ishft(nc2,-20),63) !6 bits dat(7)=iand(ishft(nc2,-14),63) !6 bits dat(8)=iand(ishft(nc2, -8),63) !6 bits dat(9)=iand(ishft(nc2, -2),63) !6 bits dat(10)=16*iand(nc2,3)+iand(ishft(ng,-12),15) !2+4 bits dat(11)=iand(ishft(ng,-6),63) dat(12)=iand(ng,63) return end