subroutine packmsg(msg,dat,text)

  parameter (NBASE=37*36*10*27*27*27)
  parameter (NBASE2=262178562)
  character*22 msg
  integer dat(12)
  character*12 c1,c2
  character*4 c3
  character*6 grid6
  logical text1,text2,text3,text

  text=.false.
! Convert all letters to upper case
  iz=22
  do i=1,22
     if(msg(i:i).ge.'a' .and. msg(i:i).le.'z')                       &
          msg(i:i)= char(ichar(msg(i:i))+ichar('A')-ichar('a'))
     if(msg(i:i).ne.' ') iz=i
  enddo
  do iter=1,5                           !Collapse multiple blanks into one
     ib2=index(msg(1:iz),'  ')
     if(ib2.lt.1) go to 5
     msg=msg(1:ib2)//msg(ib2+2:)
     iz=iz-1
  enddo

! See if it's a CQ message
5 if(msg(1:3).eq.'CQ ') then
     i=3
! ... and if so, does it have a reply frequency?
     if(msg(4:4).ge.'0' .and. msg(4:4).le.'9' .and.                  &
          msg(5:5).ge.'0' .and. msg(5:5).le.'9' .and.                &
          msg(6:6).ge.'0' .and. msg(6:6).le.'9') i=7
     go to 1
  endif

  do i=1,22
     if(msg(i:i).eq.' ') go to 1       !Get 1st blank
  enddo
  go to 10                             !Consider msg as plain text
      
1 ia=i
  c1=msg(1:ia-1)
  do i=ia+1,22
     if(msg(i:i).eq.' ') go to 2       !Get 2nd blank
  enddo
  go to 10                             !Consider msg as plain text

2 ib=i
  c2=msg(ia+1:ib-1)

  do i=ib+1,22
     if(msg(i:i).eq.' ') go to 3       !Get 3rd blank
  enddo
  go to 10                             !Consider msg as plain text

3 ic=i
  c3='    '
  if(ic.ge.ib+1) c3=msg(ib+1:ic)
  if(c3.eq.'OOO ') c3='    '           !Strip out the OOO flag
  call getpfx1(c1,k1,junk)
  call packcall(c1,nc1,text1)
  call getpfx1(c2,k2,nv2)
  call packcall(c2,nc2,text2)
  if(nv2.eq.0) then
     if(k1.lt.0 .or. k2.lt.0 .or. k1*k2.ne.0) go to 10
     if(k2.gt.0) k2=k2+450
     k=max(k1,k2)
     if(k.gt.0) then
        call k2grid(k,grid6)
        c3=grid6(:4)
     endif
  endif
  call packgrid(c3,ng,text3)
  if(nv2.eq.0 .and. (.not.text1) .and. (.not.text2) .and.           &
       (.not.text3)) go to 20
  if(nv2.gt.0) then
     if(nv2.eq.1) then
        if(c1(1:3).eq.'CQ ')  nc1=262178563 + k2
        if(c1(1:4).eq.'QRZ ') nc1=264002072 + k2 
        if(c1(1:3).eq.'DE ')  nc1=265825581 + k2
     endif
     if(nv2.eq.2) then
        if(c1(1:3).eq.'CQ ')  nc1=267649090 + k2
        if(c1(1:4).eq.'QRZ ') nc1=267698375 + k2
        if(c1(1:3).eq.'DE ')  nc1=267747660 + k2
     endif
     go to 20
  endif

! The message will be treated as plain text.
10 text=.true.
  call packtext(msg,nc1,nc2,ng)
  ng=ng+32768

! Encode data into 6-bit words
20 dat(1)=iand(ishft(nc1,-22),63)               !6 bits
  dat(2)=iand(ishft(nc1,-16),63)                !6 bits
  dat(3)=iand(ishft(nc1,-10),63)                !6 bits
  dat(4)=iand(ishft(nc1, -4),63)                !6 bits
  dat(5)=4*iand(nc1,15)+iand(ishft(nc2,-26),3)  !4+2 bits
  dat(6)=iand(ishft(nc2,-20),63)                !6 bits
  dat(7)=iand(ishft(nc2,-14),63)                !6 bits
  dat(8)=iand(ishft(nc2, -8),63)                !6 bits
  dat(9)=iand(ishft(nc2, -2),63)                !6 bits
  dat(10)=16*iand(nc2,3)+iand(ishft(ng,-12),15) !2+4 bits
  dat(11)=iand(ishft(ng,-6),63)
  dat(12)=iand(ng,63)

  return
end subroutine packmsg