WSJT-X/sync.f
J C Dutton c2ceb42b28 Summary: Merge in linux branch
svn+ssh://svn.berlios.de/svnroot/repos/wsjt/WSJT/branches/linux
merged into
svn+ssh://svn.berlios.de/svnroot/repos/wsjt/trunk



git-svn-id: svn+ssh://svn.code.sf.net/p/wsjt/wsjt/trunk@155 ab8295b8-cf94-4d9e-aec4-7959e3be5d79
2006-04-05 20:07:32 +00:00

88 lines
2.2 KiB
Fortran

subroutine sync(y1,y2,y3,y4,npts,jpk,baud,bauderr)
C Input data are in the y# arrays: detected sigs in four tone-channels,
C before decimation by NSPD.
parameter (NSPD=25)
real y1(npts)
real y2(npts)
real y3(npts)
real y4(npts)
real zf(NSPD)
real tmp1
real tmp2
complex csum
integer nsum(NSPD)
real z(65538) !Ready for FSK110
complex cz(0:32768)
equivalence (z,cz)
data twopi/6.283185307/
do i=1,NSPD
zf(i)=0.0
nsum(i)=0
enddo
do i=1,npts
a1=max(y1(i),y2(i),y3(i),y4(i)) !Find the largest one
if(a1.eq.y1(i)) then !Now find 2nd largest
a2=max(y2(i),y3(i),y4(i))
else if(a1.eq.y2(i)) then
a2=max(y1(i),y3(i),y4(i))
else if(a1.eq.y3(i)) then
a2=max(y1(i),y2(i),y4(i))
else
a2=max(y1(i),y2(i),y3(i))
endif
z(i)=1.e-6*(a1-a2) !Subtract 2nd from 1st
j=mod(i-1,NSPD)+1
zf(j)=zf(j)+z(i)
nsum(j)=nsum(j)+1
enddo
n=log(float(npts))/log(2.0)
nfft=2**(n+1)
call zero(z(npts+1),nfft-npts)
call xfft(z,nfft)
C Now find the apparent baud rate.
df=11025.0/nfft
zmax=0.
ia=391.0/df !Was 341/df
ib=491.0/df !Was 541/df
do i=ia,ib
z(i)=real(cz(i))**2 + aimag(cz(i))**2
if(z(i).gt.zmax) then
zmax=z(i)
baud=df*i
endif
enddo
C Find phase of signal at 441 Hz.
csum=0.
do j=1,NSPD
pha=j*twopi/NSPD
csum=csum+zf(j)*cmplx(cos(pha),-sin(pha))
enddo
tmp1=aimag(csum)
tmp2=real(csum)
pha=-atan2(tmp1,tmp2)
jpk=nint(NSPD*pha/twopi)
if(jpk.lt.1) jpk=jpk+NSPD
C The following is nearly equivalent to the above. I don't know which
C (if either) is better.
c zfmax=-1.e30
c do j=1,NSPD
c if(zf(j).gt.zfmax) then
c zfmax=zf(j)
c jpk2=j
c endif
c enddo
bauderr=(baud-11025.0/NSPD)/df !Baud rate error, in bins
return
end