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70 lines
1.5 KiB
Fortran
70 lines
1.5 KiB
Fortran
subroutine ffft(d,npts,isign,ireal)
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C Fourier transform of length npts=2**k, performed in place.
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C Input data in array d, treated as complex if ireal=0, and as real if ireal=1.
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C In either case the transform values are returned in array d, treated as
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C complex. The DC term is d(1), and d(npts/2+1) is the term at the Nyquist
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C frequency. The basic algorithm is the same as Norm Brenner's FOUR1, and
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C uses radix-2 transforms.
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C J. H. Taylor, Princeton University.
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complex d(npts),t,w,wstep,tt,uu
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data pi/3.14159265359/
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C Shuffle the data to bit-reversed order.
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imax=npts/(ireal+1)
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irev=1
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do 5 i=1,imax
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if(i.ge.irev) go to 2
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t=d(i)
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d(i)=d(irev)
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d(irev)=t
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2 mmax=imax/2
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3 if(irev.le.mmax) go to 5
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irev=irev-mmax
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mmax=mmax/2
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if(mmax.ge.1) go to 3
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5 irev=irev+mmax
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C The radix-2 transform begins here.
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api=isign*pi/2.
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mmax=1
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6 istep=2*mmax
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wstep=cmplx(-2.*sin(api/mmax)**2,sin(2.*api/mmax))
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w=1.
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do 9 m=1,mmax
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C This in the inner-most loop -- optimization here is important!
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do 8 i=m,imax,istep
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t=w*d(i+mmax)
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d(i+mmax)=d(i)-t
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8 d(i)=d(i)+t
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9 w=w*(1.+wstep)
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mmax=istep
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if(mmax.lt.imax) go to 6
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if(ireal.eq.0) return
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C Now complete the last stage of a doubled-up real transform.
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jmax=imax/2 + 1
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wstep=cmplx(-2.*sin(isign*pi/npts)**2,sin(isign*pi/imax))
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w=1.0
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d(imax+1)=d(1)
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do 10 j=1,jmax
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uu=cmplx(real(d(j))+real(d(2+imax-j)),aimag(d(j)) -
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+ aimag(d(2+imax-j)))
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tt=w*cmplx(aimag(d(j))+aimag(d(2+imax-j)),-real(d(j)) +
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+ real(d(2+imax-j)))
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d(j)=uu+tt
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d(2+imax-j)=conjg(uu-tt)
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10 w=w*(1.+wstep)
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return
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end
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