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https://github.com/saitohirga/WSJT-X.git
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a6722648c7
git-svn-id: svn+ssh://svn.code.sf.net/p/wsjt/wsjt/branches/wsjtx@2779 ab8295b8-cf94-4d9e-aec4-7959e3be5d79
112 lines
3.2 KiB
Fortran
112 lines
3.2 KiB
Fortran
subroutine packmsg(msg,dat,text)
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parameter (NBASE=37*36*10*27*27*27)
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parameter (NBASE2=262178562)
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character*22 msg
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integer dat(12)
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character*12 c1,c2
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character*4 c3
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character*6 grid6
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logical text1,text2,text3,text
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text=.false.
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! Convert all letters to upper case
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iz=22
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do i=1,22
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if(msg(i:i).ge.'a' .and. msg(i:i).le.'z') &
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msg(i:i)= char(ichar(msg(i:i))+ichar('A')-ichar('a'))
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if(msg(i:i).ne.' ') iz=i
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enddo
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do iter=1,5 !Collapse multiple blanks into one
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ib2=index(msg(1:iz),' ')
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if(ib2.lt.1) go to 5
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msg=msg(1:ib2)//msg(ib2+2:)
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iz=iz-1
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enddo
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! See if it's a CQ message
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5 if(msg(1:3).eq.'CQ ') then
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i=3
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! ... and if so, does it have a reply frequency?
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if(msg(4:4).ge.'0' .and. msg(4:4).le.'9' .and. &
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msg(5:5).ge.'0' .and. msg(5:5).le.'9' .and. &
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msg(6:6).ge.'0' .and. msg(6:6).le.'9') i=7
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go to 1
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endif
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do i=1,22
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if(msg(i:i).eq.' ') go to 1 !Get 1st blank
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enddo
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go to 10 !Consider msg as plain text
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1 ia=i
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c1=msg(1:ia-1)
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do i=ia+1,22
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if(msg(i:i).eq.' ') go to 2 !Get 2nd blank
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enddo
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go to 10 !Consider msg as plain text
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2 ib=i
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c2=msg(ia+1:ib-1)
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do i=ib+1,22
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if(msg(i:i).eq.' ') go to 3 !Get 3rd blank
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enddo
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go to 10 !Consider msg as plain text
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3 ic=i
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c3=' '
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if(ic.ge.ib+1) c3=msg(ib+1:ic)
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if(c3.eq.'OOO ') c3=' ' !Strip out the OOO flag
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call getpfx1(c1,k1,junk)
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call packcall(c1,nc1,text1)
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call getpfx1(c2,k2,nv2)
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call packcall(c2,nc2,text2)
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if(nv2.eq.0) then
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if(k1.lt.0 .or. k2.lt.0 .or. k1*k2.ne.0) go to 10
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if(k2.gt.0) k2=k2+450
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k=max(k1,k2)
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if(k.gt.0) then
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call k2grid(k,grid6)
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c3=grid6(:4)
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endif
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endif
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call packgrid(c3,ng,text3)
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if(nv2.eq.0 .and. (.not.text1) .and. (.not.text2) .and. &
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(.not.text3)) go to 20
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if(nv2.gt.0) then
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if(nv2.eq.1) then
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if(c1(1:3).eq.'CQ ') nc1=262178563 + k2
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if(c1(1:4).eq.'QRZ ') nc1=264002072 + k2
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if(c1(1:3).eq.'DE ') nc1=265825581 + k2
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endif
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if(nv2.eq.2) then
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if(c1(1:3).eq.'CQ ') nc1=267649090 + k2
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if(c1(1:4).eq.'QRZ ') nc1=267698375 + k2
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if(c1(1:3).eq.'DE ') nc1=267747660 + k2
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endif
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go to 20
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endif
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! The message will be treated as plain text.
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10 text=.true.
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call packtext(msg,nc1,nc2,ng)
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ng=ng+32768
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! Encode data into 6-bit words
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20 dat(1)=iand(ishft(nc1,-22),63) !6 bits
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dat(2)=iand(ishft(nc1,-16),63) !6 bits
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dat(3)=iand(ishft(nc1,-10),63) !6 bits
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dat(4)=iand(ishft(nc1, -4),63) !6 bits
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dat(5)=4*iand(nc1,15)+iand(ishft(nc2,-26),3) !4+2 bits
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dat(6)=iand(ishft(nc2,-20),63) !6 bits
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dat(7)=iand(ishft(nc2,-14),63) !6 bits
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dat(8)=iand(ishft(nc2, -8),63) !6 bits
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dat(9)=iand(ishft(nc2, -2),63) !6 bits
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dat(10)=16*iand(nc2,3)+iand(ishft(ng,-12),15) !2+4 bits
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dat(11)=iand(ishft(ng,-6),63)
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dat(12)=iand(ng,63)
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return
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end subroutine packmsg
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