WSJT-X/lib/packcall.f

80 lines
2.2 KiB
Fortran

subroutine packcall(callsign,ncall,text)
C Pack a valid callsign into a 28-bit integer.
parameter (NBASE=37*36*10*27*27*27)
character callsign*6,c*1,tmp*6
logical text
text=.false.
C Work-around for Swaziland prefix:
if(callsign(1:4).eq.'3DA0') callsign='3D0'//callsign(5:6)
if(callsign(1:3).eq.'CQ ') then
ncall=NBASE + 1
if(callsign(4:4).ge.'0' .and. callsign(4:4).le.'9' .and.
+ callsign(5:5).ge.'0' .and. callsign(5:5).le.'9' .and.
+ callsign(6:6).ge.'0' .and. callsign(6:6).le.'9') then
read(callsign(4:6),*) nfreq
ncall=NBASE + 3 + nfreq
endif
return
else if(callsign(1:4).eq.'QRZ ') then
ncall=NBASE + 2
return
else if(callsign(1:3).eq.'DE ') then
ncall=267796945
return
endif
tmp=' '
if(callsign(3:3).ge.'0' .and. callsign(3:3).le.'9') then
tmp=callsign
else if(callsign(2:2).ge.'0' .and. callsign(2:2).le.'9') then
if(callsign(6:6).ne.' ') then
text=.true.
return
endif
tmp=' '//callsign(:5)
else
text=.true.
return
endif
do i=1,6
c=tmp(i:i)
if(c.ge.'a' .and. c.le.'z')
+ tmp(i:i)=char(ichar(c)-ichar('a')+ichar('A'))
enddo
n1=0
if((tmp(1:1).ge.'A'.and.tmp(1:1).le.'Z').or.tmp(1:1).eq.' ') n1=1
if(tmp(1:1).ge.'0' .and. tmp(1:1).le.'9') n1=1
n2=0
if(tmp(2:2).ge.'A' .and. tmp(2:2).le.'Z') n2=1
if(tmp(2:2).ge.'0' .and. tmp(2:2).le.'9') n2=1
n3=0
if(tmp(3:3).ge.'0' .and. tmp(3:3).le.'9') n3=1
n4=0
if((tmp(4:4).ge.'A'.and.tmp(4:4).le.'Z').or.tmp(4:4).eq.' ') n4=1
n5=0
if((tmp(5:5).ge.'A'.and.tmp(5:5).le.'Z').or.tmp(5:5).eq.' ') n5=1
n6=0
if((tmp(6:6).ge.'A'.and.tmp(6:6).le.'Z').or.tmp(6:6).eq.' ') n6=1
if(n1+n2+n3+n4+n5+n6 .ne. 6) then
text=.true.
return
endif
ncall=nchar(tmp(1:1))
ncall=36*ncall+nchar(tmp(2:2))
ncall=10*ncall+nchar(tmp(3:3))
ncall=27*ncall+nchar(tmp(4:4))-10
ncall=27*ncall+nchar(tmp(5:5))-10
ncall=27*ncall+nchar(tmp(6:6))-10
return
end