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Fix two small typos.
git-svn-id: svn+ssh://svn.code.sf.net/p/wsjt/wsjt/branches/wsjtx@6369 ab8295b8-cf94-4d9e-aec4-7959e3be5d79
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@ -246,7 +246,7 @@ The minimum Hamming distance of the JT65 code is
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\end_inset
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, which means that any particular codeword differs from all other codewords
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in at least 52 or the 63 symbol positions.
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in at least 52 of the 63 symbol positions.
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\end_layout
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@ -849,7 +849,7 @@ The FT algorithm uses quality indices made available by a noncoherent 64-FSK
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\end_inset
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of the symbol's fractional power
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\begin_inset Formula $p_{1,\,j}$
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\begin_inset Formula $p_{1,\, j}$
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\end_inset
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in a sorted list of
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@ -919,7 +919,7 @@ t educated guesses to select symbols for erasure.
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, the soft distance between the received word and the codeword:
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\begin_inset Formula
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\begin{equation}
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d_{s}=\sum_{j=1}^{n}\alpha_{j}\,(1+p_{1,\,j}).\label{eq:soft_distance}
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d_{s}=\sum_{j=1}^{n}\alpha_{j}\,(1+p_{1,\, j}).\label{eq:soft_distance}
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\end{equation}
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\end_inset
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@ -937,7 +937,7 @@ Here
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\end_inset
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if the received symbol and codeword symbol are different, and
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\begin_inset Formula $p_{1,\,j}$
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\begin_inset Formula $p_{1,\, j}$
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\end_inset
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is the fractional power associated with received symbol
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@ -981,7 +981,7 @@ In practice we find that
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\begin_layout Standard
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\begin_inset Formula
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\begin{equation}
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u=\frac{1}{n}\sum_{j=1}^{n}S(c_{j},\,j).\label{eq:u-metric}
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u=\frac{1}{n}\sum_{j=1}^{n}S(c_{j},\, j).\label{eq:u-metric}
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\end{equation}
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\end_inset
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@ -1014,7 +1014,7 @@ The correct JT65 codeword produces a value for
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bins containing noise only.
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Thus, if the spectral array
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\begin_inset Formula $S(i,\,j)$
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\begin_inset Formula $S(i,\, j)$
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\end_inset
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has been normalized so that the average value of the noise-only bins is
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@ -1263,7 +1263,7 @@ For each received symbol, define the erasure probability as 1.3 times the
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a priori
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\emph default
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symbol-error probability determined from soft-symbol information
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\begin_inset Formula $\{p_{1}\textrm{-rank},\,p_{2}/p_{1}\}$
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\begin_inset Formula $\{p_{1}\textrm{-rank},\, p_{2}/p_{1}\}$
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\end_inset
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.
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@ -1595,7 +1595,7 @@ If
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\begin_inset Formula $u$
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\end_inset
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is the largest found so far, presevre any previous value of
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is the largest found so far, preserve any previous value of
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\begin_inset Formula $u_{1}$
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\end_inset
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